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x^2+xy+y^2=12
dy/dx = -(2x+y)/(x+2y)
Am I right?
No, its mathS.
use the S, its english!!
aye.
better?
Cheers sam.
42
Well it's been about 15 years since I did that sort of stuff but I came up with same answer as you.
No. It's 12.
x=2, y=2
could be 12
could x=2, y=2
[url= http://www.wolframalpha.com/input/?i=x^2%2Bxy%2By^2%3D12 ]Have a look for yourself[/url]
RealMan, your answer is one of the two correct answers. The other is shown on travis' link
Yeah, depends on what you differentiate with respect to. Question didn't state which, so I assumed x.
Been a while since I did this but you're differentiating y with respect to x. Treat all the y's as a constant.
dy/dx [ x^2 + xy + y^2 - 12 = 0]
= 2x + y
All Travis's link has done is show you a solution to the equation. I have a sneaky feeling that I might be barking up the wrong tree here, it's been about 5 years since I differentiated anything.
Treat all the y's as a constant.
I have a sneaky feeling that I might be barking up the wrong tree here
Yep.
🙂
D'oh.