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So that d is the subject.
C = 4-d/d+3
Let's see ifvwe are right?
Tia
d=(4-3C)/(1+C)
What mefty said ( If that's correct !) 😉
Yep, I'll back up mefty's answer.
C=(4-d)/(d+3)
cd +3c = 4-d multiply both sides by d+3
cd+d=4-3c rearrange to get d on the left hand side
d(c+1) = 4-3c get d to be the subject
d= 4-3c/c+1 Same as mefty.
But 4-d/d+3 is not the same as (4-d)/(d+3) is it? d/d =1 does it not?
But then it would be impossible to solve
Gowrie's correct, if the equation is as wrightyson wrote, then the answer is 6. We're imagining that the top line is 4-d, with d + 3 on the bottom. Which is different to the original post.
But then it would be impossible to solve
no, d/d will always be 1.
The equation isn't impossible but the question is as they would be no d to make the subject.
Just checked, it is as I wrote it. Still debating the answer here.
cd+d=4-3c rearrange to get d on the left hand side
d(c+1) = 4-3c get d to be the subject
Can't work out this move?
Wrightyson:
- if your referring to how you get from d(C+1)=4-3C to the final result, whatever you do to one side of the equation you do to the other so dividing both sides by (C+1) leaves you with d on the left side and (4-3C)/(C+1) on the right; strictly speaking the left side becomes d times 1 which is d.
No it was the move before. Still haven't got the hang of the new quote button!!!
If you multiply out d(c+1) you get dc (same as cd) + d*1 (which is d)
Got ya 👍
I'm with Gowrie. BODMAS - brackets, orders, division, multiplication, addition, subtraction. There are no brackets so the first thing to do is the d/d division = 1?
[i]alisonsmiles wrote:[/i]
I’m with Gowrie. BODMAS
Yeah, but it's SBODMAS* - S for solution. If you start by dividing d/d there isn't a solution for d.
*I just made that up, but it's a legit first principle which results in implied brackets
If you apply the rules of bodmas, it becomes impossible to express in terms of d.
Edit.
Wow, did my phone really take 8 minutes to post that? I certain read the slash as separating the numerator and the denominator
Yeah, but it’s SBODMAS* – S for solution. If you start by dividing d/d there isn’t a solution for d.
*I just made that up, but it’s a legit first principle which results in implied brackets
Sloppy to give it to you in a form that can't be solved, IMO
I think it all depends on exactly how the equation is written. Text boxes on a forum don't lend themselves to mathematical expressions.
If it's written as example 1 then mefty is right. If it's written as example 2 (i.e. how OP has typed it here) then Gowrie is right.
I suspect it's written as per example 1.
FO - you could well be right with 1 above. I withdraw my accusation. 🙂