Maths homework help
 

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[Closed] Maths homework help

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Trying to "help" with some maths revision, its been along time since I've done anything like this.

Can anyone help with the following:

3(2x + 4) = 5x + 17

I've got this far:

3(2x + 4) = 5x + 17
6x + 12 = 5x +17
6x = 5x + 5

So *if* I'm correct thus far Im confident that x = 5. But i wouldn't be certain how to show my working.
And I'm not that confident Im actually correct 🙄

Thanks


 
Posted : 06/05/2017 5:00 pm
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That'll do and you can be sure you're correct as 5 satisfies the original equation.

You're a natural 🙂


 
Posted : 06/05/2017 5:07 pm
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Spot on


 
Posted : 06/05/2017 5:12 pm
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'shudders'

🙁


 
Posted : 06/05/2017 5:15 pm
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what would be the step to get from

6x = 5x + 5
to
x = 5

for the purposes of explanation...
I know its x = 5 in my head, but cant show how i arrived at that


 
Posted : 06/05/2017 5:15 pm
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The only 'improvement' (and it would be very marginal) is that your last bit is inferred as opposed to shown:

6x = 5x + 5

Subtract 5x from both sides

=> 6x-5x = 5

X = 5


 
Posted : 06/05/2017 5:16 pm
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Unless I'm hopelessly out of date, I would expect that they would want to see the intermediate workings, which if things have remained unchanged since I was at school (unlikely), would mean something like this:

6x + 12 = 5x + 17
6x - 5x = 17 - 12
x = 5


 
Posted : 06/05/2017 5:19 pm
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Thanks all!
Might be back later with some more! :-/


 
Posted : 06/05/2017 5:44 pm
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Remember to try and get all the variables on the left of the = and the numbers on the right. I'm sure there's probably a name for that process...


 
Posted : 06/05/2017 5:55 pm
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sod off - we've shown you how to do it, you're on your own now.

(can someone help my daughter with % calcs. I can do them but I can't explain adequately to get her to see it. Seriously; it's not the calcs themselves, it's knowing when to use which:

eg: Polly sees a dress in the shop. The label price is £15 but there is a special offer of 20% off. How much does the dress cost?

Ans: £15 x 20% = £3, therefore dress is 15-3 = £12
(or - 20% off means you pay 100-20 = 80%. £15 x 80% = £12)

vs

Polly buys a dress in the 20% off sale. She pays £12 for the dress, what was the original price.

Ans: £12 / 0.8 = £15

But she keeps using £12 x 1.2 to find the original price = £14.40 = wrong.

vs: Polly buys a dress in America and can claim the sale tax of 6.5% back. The price she pays is $15.97, what was the cost of the dress without tax

Ans: $15.97 / 1.065 = $15


 
Posted : 06/05/2017 5:57 pm
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But she keeps using £12 x 1.2 to find the original price = £14.40 = wrong.
get her to do a really obvious one like 50% discount on a tenner - with real pound coins


 
Posted : 06/05/2017 6:05 pm
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gauss1777

Interesting user name on a maths thread 🙂


 
Posted : 06/05/2017 6:09 pm
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she can do the first no probs, it's flipping it to back calculate it.

And in fact if I get her to do the first one first she then sees the second. But give her the second in isolation, she has a mental block.


 
Posted : 06/05/2017 6:19 pm
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"Polly buys a dress in the 20% off sale. She pays £12 for the dress, what was the original price.

Ans: £12 / 0.8 = £15"

I like your method best,

perhaps a slight tweak to 0.8x=12
x=12/0.8
X=15. where x is the original amount would make it clearer why you divided?

but I have often seen it taught:

80%--------- 12
1%------------12/80=0.15
100%----------100x0.15=15

Hope that's clear.

Oh and Rob, I'm a Gauss fanboi - as they say


 
Posted : 06/05/2017 6:28 pm
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Ta, will try it.


 
Posted : 06/05/2017 6:46 pm

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