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Hi guys, I've dug out some rotten concrete and I intend to fill it with new. the hole I have equates to approx 0.1 meter^3 (if my calculations are right).
Roughly how much dry cement and aggregate will I need to create enough to fill above hole?
thanks in advance
Typical density of concrete is about 2400 kg/m^3 - so you'll need 1/10th of this for your 0.1 m^3 hole. Very rough mix quantities will be 1 part cement, 2 parts sand and 4 parts coarse aggregate - so if you're buying bagged ingredients from a DIY store then 2 bags of cement, 2 bags of sand and 4 bags of gravel should be about right (assuming 25 kg bags of cement and 40 kg bags of sand and gravel).
Depends on how strong you need the mix tbh. I would allow 8 x 25kg bags of ballast and 32(ish)kg cement. A single bag of cement may just be enough but really depends on the strength you need.
approx 0.1 meter^3 (if my calculations are right).
So what are the measurements???
0.1m cubed? That is one litre. Density has nothing to do with the volume required.
1.3(w) x 1.8(l) x 0.04(d) = 0.094m^3??
doesn't need to be too strong, it's an internal floor that will be covered with either laminate or carpet and underlay.
Being only 40mm deep I might be tempted to go with a deep fill self leveling compound or one mix (all 25 kg bags 1 cement, 2 sand 4 aggregate) and then top it up with a self leveling compound
will sharp sand be an adequate aggregate or should I use something more coarse?
40mm deep should only require a sand / cement screed i.e. no aggregate.
7 or 8 25kg bags of coarse sand and a couple of bags of cement. Could be left slightly low (about 3 - 5mm) and finished with self levelling as carlos said.
Edit - if you want to add aggregate for strength use a 10mm or grano dust.