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A colleague here has an equation:
tan(ax)+bx = c
he wants to know x, how do you take a factor of x out of the first part of the equation?
it's been almost 20 years, and I can't remember!
Would be tricky, x has lots of values.
arctan (ax) = c - bx
Hmmm I'm not sure you can, but my A-level is somewhat historic!
With 4 unknowns you are going to need 4 equations n'est-ce pas?
With 4 unknowns you are going to need 4 equations n'est-ce pas?
a, b and c aren't unknowns, they're constants.
For example, if you take a=2, b=3, c=4, the equation becomes this
Which would be tricky to solve.
a, b and c aren't unknowns, they're constants.
Fair enough...
apparently he knows a, b and c. needs to know x.
I've told him to plot it graphically guessing the range of x.
we've just put it into excel and we're not far off getting the answer. .....
Could re-arrange into the form x=g(x) and iterate?
Yes, I think numerical root finding would be your best bet.
So do y=tan(ax)+bx-c then solve for y=0
I have access to powerful graphing tools, if you give me a b and c I can find the answers for you.
So do y=tan(ax)+bx-c then solve for y=0
Or x=[c-tan(ax)]/b and use iteration...
Realman, cheers. but he's gone home now and hasn't quite worked out a,b and C yet (although he can).
I think excel will do the job!
Thanks for backing me up on the confusing impossibility of doing this algebraically and it isn't just my aging mathematically incompetent brain.
Ok, no worries.
Is excellent for things like this, and could give you several answers and a simple graph.
Or x=[c-tan(ax)]/b and use iteration...
Yeah, same thing really.