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So I'm in the process of going 1 x 11 with Srams 10/42 cassette. Currently I use 26/36 and 11/36 cassette. I've brought a 36 ring for the front for the 11 speed conversion. To calculate the get ratio do I just divide the front with the rear and compare numbers?
I'm concerned my 36 tooth ring will be too big. What size ring at the front do I need to have to have the same ratio as the 26/36 setup at the moment?
Thanks
To calculate the get ratio do I just divide the front with the rear and compare numbers?
Yes, so long as the wheel size stays the same.
Chainring/sprocket x wheel size in inches
So your lowest gear at the moment is (26/36) x 26 (or 27.5 or 29 as applicable)
And your highest gear is (36/11) x (wheel size).
Lower the number the lower the gear.
Then it's just a case of picking something that gets you in between that range with an 11sp cassette.
Wheel x Chainring divided by sprocket = gear in inches
30
26:36 rougly equals 30:42
Adding gear inches is an unnecessary complication unless you want to compare across bikes IMO.
Work out ratios of chainring:cassette sprocket, just divide one by the other. 36 is big, it'll give you a bigger gear than you currently have and compromise at the other end. 32 or 34 would probably be a better bet.
Do you use 26:36t though. A 30t ring will give that ratio But your top gear will be alot lower. To keep your top gear ratio you will need a 33t ring (actualky a 32.7T ring but thats not possible). 32t is the comprimise. You must be a spinner though.
Not so much with a 10t sprocket. Remember that's basically 10% smaller than an 11t.
Do you use 26:36t though
Yes, because I can and it gives me the opportunity to be lazy. I was thinking today that I might not miss this gear because it is very low.